Question

In'a potentiometer experiment, a cell of emf 1.5V connected in the secondary
circuit gives a balancing length of 165 cm of the wire. If a resistance of 52 is
connected parallel to the cell, the balancing length of the wire is 150 cm. The
internal resistance of the cell is
A) 502
B) 1.592
D) 122
C) 0.502​

Answer 1

$\bold{ \huge{ \red{ \underline{Answer:-}}}}$

Given:-

➤ External resistance = 5Ω

➤ Both lengths are 165 cm and 150 cm.

Solution:-

In potentiometeric circuit we know that,

$= > \bold{r = R( \frac{l {}_{1} }{l{}_{2} - 1} )}$

Hence putting all the values we get,

$\bold{ = > r = 5( \frac{165}{150 - 1} ) }$

$\bold{= \underline{ 0.5Ω}}$

_____________

Hence, shown.