Physics, asked by ghatemanish319, 1 month ago


In a potentiometer experiment of a cell of emf 1.25V gives balancing length of 30cm. If the cell is
replacd by another cell, balancing length is found to be 40cm. What is the emf of second cell?​

Answers

Answered by mandanageswararao9
0

Explanation:

Given : E

1

=1.25 V l

1

=30 cm l

2

=40 cm

Emf of the cell E∝l

E

1

E

2

=

l

1

l

2

1.25

E

2

=

30

40

⟹ E

2

=1.67 V

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