Question

In a ∆ PQR ,2 angle P = 3 angle Q = 6 angle R , find the measure of angle P, angle Q , and angle R​

Answer 1

Answer:

angle P = 90 degrees

angle Q = 60 degrees

angle R = 30 degrees

Step-by-step explanation:

2 angle P = 3 angle Q = 6 angle R

let angle P = x

then

2x = 3 angle Q = 6 angle R

so,

angle Q = 2x/3

angle R = 2x/6 = x/3

in a triangle, sum of three angles is always equal to 180 degrees.

so,

x+2x/3+x/3=180

(3x+2x+x)/3=180

6x/3=180

x=180×3/6

x=90

so

angle P=90 degrees

2 angle P = 3 angle Q

2×90=3 angle Q

angle Q =2×90/3=60

also

2 angle P = 6 angle R

2×90 = 6 angle R

angle R = 2×90/6=30

angle R = 30 degrees

hence the answer.

Answer 2

Answer:

angle P = 90⁰

angle Q = 60⁰

angle R = 30⁰

Step-by-step explanation:

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