In a ∆ PQR, angle Q = 90⁰
, = 6 cm angle = 60⁰
, then find the lengths of and R ?
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Let PQR is a right angled triangle.
PQ = 6cm, Angle RPQ = 60degrees = Angle P
tan 60degrees = QR/PR = √3 = QR/6 = QR = 6√3
sin 60degrees = QR/PR = √3/2 = 6√3/PR
= PR = 6√3 x 2/√3
= 6 x 2
= 12
Therefore, the length of QR is 6√3 centimetres.
Therefore, the length of PR is 12 centimetres.
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