Question

in a ∆pqr angle q=90 if pq=10cm and pr 15 cm then the value of tan2 p+sec2p+15​

Answer 1

It is given in the question that PQR is a right-angled triangle and it is right-angled at P.

So, we can apply the Pythagoras theorem here.

If it is right-angled at P then the side opposite to P will be the hypotenuse of the triangle i.e. QR and the other sides are given as PQ = 10 cm and PR = 24 cm.

Now, by applying the Pythagoras theorem i.e. in a right-angled triangle, the square of the hypotenuse is equal to the sum of the square of the other two sides, we can find QR.

Given, PQ = 10 cm, PR = 24 cm and QR =?

By applying Pythagoras theorem in triangle PQR, we get (Hypotenuse)2 = (Perpendicular)2 + (Base)2

(QR)2 = (PQ)2 + (PR)2

(QR)2 = (10)2 + (24)2

(QR)2 = 100 + 576

(QR)2 = 676

QR = 26 cm

Thus, QR is equal to 26 cm.

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