In A PQR, angle R = 90° and PQ= 26cm, QS= 18cm
and PS=10cm. Find the length of PR and SR.
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Answer:
Given:
PQ = 8 cm
QR = 6 cm
PR = ?
∠PQR = 90°
According to Pythagoras Theorem,
(PR)2 = (PQ)2 + (QR)2
PR2 = 82 + 62
PR2 = 64 + 36
PR2 = 100
∴ PR = √100 = 10 cm
(ii) Given :
PR = 34 cm
QR = 30 cm
PQ = ?
∠PQR = 90°
According to Pythagoras Theorem,
(PR)2 = (PQ)2 + (QR)2
(34)2 = PQ2 + (30)2
1156 = PQ2 + 900
1156 - 900 = PQ2
256 = PQ2
∴ PQ = 16 cm
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