In a∆ PQR , if 2 triangle P =3 triangle Q=6 triangle R , find the measure of triangle p triangle Q and triangle R
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2∠P=3∠Q 3∠Q=6∠R
∠P=3/2∠Q(1) ∠R=1/2∠Q (2)
By angle sum property in triangle PQR
∠P+∠Q+∠R=180°
3/2∠Q+∠Q+1/2∠Q=180° (FROM 1 AND 2)
6∠Q/2=180°
3∠Q=180°
∠Q=60°
∠P=3/2×60°=90° ∠Q=60°
∠R=1/2×60=30°
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