Question

In a ΔPQR, If 3 sin P + 4 cos Q = 6 and 4 sin Q + 3 cos P = 1, then the angle R is equal to:(a) $\frac{5\pi}{6}$(b) $\frac{\pi}{6}$(c) $\frac{\pi}{4}$(d) $\frac{3\pi}{4}$

Answer 1

Option A is correct option

Hope it helps u

Answer 2

In a ΔPQR, If 3 sin P + 4 cos Q = 6 and 4 sin Q + 3 cos P = 1, then the angle R is equal to:(a) $\frac{5\pi}{6}$✔(b) $\frac{\pi}{6}$(c) $\frac{\pi}{4}$(d) $\frac{3\pi}{4}$