Math, asked by anamikaiyengar3665, 11 months ago

In a ΔPQR, If 3 sin P + 4 cos Q = 6 and 4 sin Q + 3 cos P = 1, then the angle R is equal to:(a) \frac{5\pi}{6}(b) \frac{\pi}{6}(c) \frac{\pi}{4}(d) \frac{3\pi}{4}

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Answered by Anonymous
0

Option A is correct option

Hope it helps u

Answered by Anonymous
0

In a ΔPQR, If 3 sin P + 4 cos Q = 6 and 4 sin Q + 3 cos P = 1, then the angle R is equal to:(a) \frac{5\pi}{6}✔(b) \frac{\pi}{6}(c) \frac{\pi}{4}(d) \frac{3\pi}{4}

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