Question

In a∆pqr, if EF||QR ,EF=5cm ,QR=8cm and PE=3.5cm ,find PQ?

Answer 1

PQ = 5.6 In a∆pqr, if EF||QR ,EF=5cm ,QR=8cm and PE=3.5cm

Step-by-step explanation:

In a∆pqr, if EF||QR

=> Δ PQR  ≈ Δ PEF

=> PQ/PE  = QR/EF

=> PQ/3.5 = 8/5

=> PQ = 28/5

=> PQ = 5.6

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Answer 2

The value of $PQ$ is $5.6\ cm$

Step-by-step explanation:

Given,

In figure,

$EF\parallel QR,EF=5\ cm,QR=8\ cm\ and\ PE=3.5\ cm$

In $\triangle PQR\ and\ \triangle PEF$,

$\angle PEF=\angle PQR$ (∵$EF\parallel QR$)

$\angle PFE=\angle PRQ$ (∵$EF\parallel QR$)

$\angle P$ common.

$\triangle PQR$≅$\triangle PEF$

So,

$\frac{PQ}{PE}=\frac{QR}{EF}$

⇒$\frac{PQ}{3.5}=\frac{8}{5}$

⇒$PQ=\frac{8}{5}\times 3.5$

⇒$PQ=5.6\ cm$

So, The value of $PQ$ is $5.6\ cm$