In A PQR, night angled at Q.
PR+ Q R = 30cm and PQ=10cm.
Determine the
tan P.
sin po cosp and
Answers
Answered by
1
Answer:
Step-by-step explanation:
In triangle PQR,
PR+QR=30 cm and PQ= 10 cm
sin 90= PQ/PR
1 = 10/PR
Therefore, PR= 10 cm
PR+ QR= 30
10+ QR= 30
So, QR = 20 cm
tan P= QR/PQ
tan P= 20/ 10
tan P= 2
sin P= QR/PR
sin P= 20/10
sin P= 2
cos P= PQ/PR
cos P = 10/10
cos P= 1
Therefore, sin P= 2; cos P= 1 and tan P= 2
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