Question

In a pqr:pQ = √8, QR = √5 PR = √3
ISAPQR a right angled triangle & If yes
which Cingle is oF 90​

Answer 1

Answer:

Longest side of ∆PQR = PQ = √8 ∴ PQ2 = (√8)2 = 8 Now, sum of the squares of the remaining sides is, QR2 + PR2 = (√5)2 + (√3)2 = 5 + 3 = 8 ∴ PQ2 = QR2 + PR2 ∴ Square of the longest side is equal to the sum of the squares of the remaining two sides. ∴ ∆PQR is a right-angled triangle. [Converse of Pythagoras theorem] Now, PQ is the hypotenuse. ∴∠PRQ = 90° [Angle opposite to hypotenuse] ∴ ∆PQR is a right-angled triangle in which ∠PRQ is of 90°.i