Question

IN a ∆PQRr,PS is the median . show that PQ+OR+PR>2PS.​

Answer 1

Answer:

From, triangle PQS, we get - PQ+QS > PS - - - (1)

And, from triangle PRS, we get - RP+SR >PS - - (2)

By doing, (1)+(2), we get - PQ+(QS+SR)+RP> (PS+PS)

So, PQ+QR+RP > 2PS (proved)

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