Question

In a process 701 J of heat is absorbed by a system and 394 J of work is done on the system. What is the change in internal energy for the process?

Answer 1

Ahoy  !!!!
______________________________________________________________
dQ= dU + dW 

dU= dW - dQ 

dU=394 - 701 

dU = - 307 J 

______________________________________________________________

Answer 2

Answer:

Explanation:

HOPE IT HELPS YOU