Question

In a process,701J of heat is absorbed by a system and 394J of work is done by the system.What is the change in internal energy for the process?​

Answer 1

Answer:

∆U = 307J

Explanation:

since....

∆Q = ∆U + W

701 = ∆U + 394

∆U = 701 - 394

∆U = 307J