In a process 701J of heat is absorbed by a system and 394J of work is done by the sy s for the process? internal energy change pressure is converted to ice at of ice 4.2 / J gC in tem. What is the change in internal energy
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According to the first law of thermodynamics,
ΔU= q + W (i)
Where, ΔU = change in internal energy for a process
q = heat
W = work
Given, q = + 701 J (Since heat is absorbed)
W = -394 J (Since work is done by the system)
Substituting the values in expression (i), we get
ΔU= 701 J + (-394 J) ΔU = 307 J
Hence, the change in internal energy for the given process is 307 J.
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