Chemistry, asked by savilla171, 11 months ago

in a process of 720 kj heat is absorb by the system and 340 kj of work is done by system what is the internal energy???
if the enthalpies of the formation of co,co2, n2o,are -110,-393,81,and 9.7kj/mole what is the enthalpy of the reaction n2o4+3co--n2o+3co2

Answers

Answered by njb007

Answer:

internal energy = -720+340 = -380.

enthalapy of formation = bro something is missing in ur question bcz there are 4 compounds and u mentioned 3 compounds with 4 enthalapies of formation ????

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in a process of 720 kj heat is absorb by the system and 340 kj of work is done by system what is the internal energy??? if the enthalpies of the formation of co,co2, n2o,are -110,-393,81,and 9.7kj/mole what is the enthalpy of the reaction n2o4+3co--n2o+3co2

Answers

in a process of 720 kj heat is absorb by the system and 340 kj of work is done by system what is the internal energy???
if the enthalpies of the formation of co,co2, n2o,are -110,-393,81,and 9.7kj/mole what is the enthalpy of the reaction n2o4+3co--n2o+3co2