Physics, asked by shivabnagally16851, 11 months ago

In a process, the pressure of an ideal gas is proportional to square of the volume of the gas. If the temperature of the gas increases in this process, then work done by this gas

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Answered by kethavathkarthiks
0

Answer:In a process, the pressure of an ideal gas is proportional to square of the volume of the gas. If the temperature of the gas increases in this process, then work done by this gas. T is increasing. So, V will also increase

Answered by Pratik272003
0

Answer: is negative

Explanation: P (proportional) V^2

So, PV^-2=const.

W.D in polytropic process

=nRt(T2-T1) /x-1 (X=-2)

= –nRt(T2-T1)

So W. D is negative

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