Question

in a progression, if Tn=2n^2+1,then find T5 and T8​

Answer 1

Answer:

Tn =2n^2 +1

T 5 is when n= 5

T5=2(5)^2 +1

T5 = 2× 25 +1

T5 = 50+1 = 51

T8=2(8)^2+1

T8= 2×64 +1

T8= 128+1

= 129