Question

In a projectile motion if maximum height is equal to the horizontal range, then what is the angle of projection?

Answer 1

Horizontal Range:

(U^2 Sin 2 (A)/g) where 'A' is the projection angle.

Maximum Height:

U^2 [Sin (A)]^2/2 g where 'U' is the projection velocity.

[Sin (A)] ^2 = 2× Sin 2 (A)

Sin (A) = 4 × Cos (A)

tan [A] = 4, A = tan~[4] where '~' is the inverse.

Answer 2

Answer:

I hope it will help you yaar