Question

In a projectile motion velocity at maximum height is

a. ucostheta/2
b.u cos theta
c.u sin theta/2
d.none of these​

Answer 1

Answer:

I depends on the angle with which you throw with respect to horizontal.

Suppose you thrown with angle an angle theta, then velocity at max height will be along Horizontal component only which is given by Ucos(theta)

In your question , if u consider angle theta , then it will be option 2

And if you consider angle theta/2, then first option is correct.

REGARDS

Answer 2

Answer:

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