Question

In a projectile motion x-direction is horizontal andy-direction is vertical. The relation between y and x is given by y = 40x – 10x2. Here x and y are in metre. The horizontal range of the projectile is

Answer 1

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=>Y = x tana (1 - x/R) ----------1

=> Y =40x – 10x²

=> Y =40x (1 - x/4 )-------------2

Compare 1 & 2 , we get that

=> R = 4 Ans
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