Question

In a proportion the first , second and third terms are 34 , 51 and 36 , respectively . Find the fourth term .
​

Answer 1

Given :-

• In a proportion the first , second and third terms are 34 , 51 and 36 , respectively.

To Find :-

• Fourth term.

Solution :-

If the four terms are in proportion a : b : c : d,

.°. a/b = c/d

Where,

• First term (a) = 34
• Second term (b) = 51
• Third term (c) = 36
• Fourth term (d) = ?

[ Putting values ]

↪ 34/51 = 36/d

↪ 34d = 51 × 36

↪ 34d = 1836

↪ d = 1836/34

↪ d = 54

Hence,

• The fourth term is 54.

Answer 2

$\sf\red{Question:}$

In a proportion the first , second and third terms are 34 , 51 and 36 , respectively . Find the fourth term.

$\sf\red{\underline{\underline{Given:-}}} \sf First,second,third~ terms~ are~ in ~proportion~ 34,~51,~36~ respectively$

$\sf\red{\underline{\underline{To~find:-}}} \sf Fourth~term$

$\sf\red{\underline{\underline{Solution:-}}} \sf Four~ terms~ are~ in ~proportion ~a:b:c:d,\\ \\ \sf Therefore, ~\dfrac{a}{b}=\dfrac{c}{d} \\ \\ \rm First ~term~(a) =34 \\ \\ \rm second~term(b)= 51 \\ \\ \rm Third~term(c)=36 \\ \\ \rm Fourth~term(d)= d \\ \\ \bold Putting~the~values : \\ \\ \rm \dfrac {34}{51}= \dfrac{36}{d} \\ \\ \implies 34d=51 \times {36} \\ \\ \implies 34d= 1836 \\ \\ \implies d=\frac{1836}{34}\\ \\ \implies D= 54$

$\bold\green{Hence,~D= 54}$