Question

In a proposition, the 1st 2nd 4th term are 32 112 217 respectively. Find the 3rd term


please tell the answer with proper steps who will give the correct answer i will make him or her the brainleast ​

Answer 1

Step-by-step explanation:

if 1st term is 32 and 2nd term is 112 and 4th term is 217 so,

3rd term=1st term +2nd term 4th term=32+112+217=361 so,

3rd term=361

Answer 2

$\large\bold{\underline{\underline{\red{✎Ｇiven:-}}}}$

• First Term = 32
• Second Term = 112
• 4th Term = 217.

( To Find 3rd Term )

$\large\bold{\underline{\underline{\red{❒ \: ꜱᴏʟᴜᴛɪᴏɴꜱ:-}}}}$

• 32:112: :x:217

$\red{ \boxed{{ \frac{32}{112 } = \frac{x}{217} }}} \\ we \: do \: (cross \: mutiplication) \\ 32 \times 217 = x \times 112 \\ = x = \frac{32 \times 217}{112} = 62$

Hence , The 3rd Terms is 62.