Question

In a public examination 90% studwnts passwd and 8800 students failed . Hiw many students appearwd and how many passed

Answer 1

Given that : In a public examination 90% students passed.

So, the percentage of failed students : 100-90 = 10%

Also given that : 8800 students failed

Now, total students appeared in the exams :

$\frac{8800 \times 100}{10} = 88000$

Thus, 88000 students appeared in the exam.

Now, number of the passing students :

$88000 \times \frac{90}{100} = 79200$

Thus, 79200 students passed in the examination.

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Answer 2

Question :-

In a public examination 90% studwnts passwd and 8800 students failed . How many students failed and how many passed?

Answer :-

Let the number of students passed be 'x'

Given , The percentage of students passed = 90%

Now, number of students failed = 100% - 90% = 10%

Now, According to the question

$\bold{ \frac{10}{100}x = 8800}$

$\bold{ \implies{x = \frac{8800 \times 100}{10}} }$

$\bold{ \implies{x = 88000}}$

Therefore, the number of students passed are 88000