Question

In a public examination, 91% students
passed and 8820 students failed.
How many students appeared for the
examination? How many students passed the exam ?​

Answer 1

Answer:

The remaining students passed that is only 6%

Answer 2

Appropriate Question :-

• $\textsf{In a public examination, 91 per cent students passed and 8820 students failed. How many students appeared for the examination? How many students passed the examination?}$

Given:-

• $\textsf{Percentage of students passed = 91 per cent.}$

• $\textsf{No. of students failed = 18.}$

To Find:-

• $\textsf{Total no. of students appeared in the examination.}$

Solution:-

$\textsf{let us suppose the total no. of students appeared in examination be x. }$

$:\implies\textsf{percentage \: of \: Failed \: Students = } \\ \\ \\ :\implies\mathbb{ = 100 - 91} \\ \\ \\ \boxed{:\implies\tt\green{Percentage \: of \: failed \: students = 9}}$

$\textsf{According to question :-}$

$:\implies\mathbb{9 \: of \: x = 18} \\ \\ \\ \\ \\ :\implies\mathbb{ \frac{9}{100} \times x = 18} \\ \\ \\ \\ \\ :\implies\mathbb{x = \frac{18 \times 100}{9} } \\ \\ \\ \\ \\ :\implies\tt{x = \dfrac{\cancel{1800}}{\cancel{9}}} \\ \\ \\ \\ \\ :\implies\star \: {\underline{\boxed{\tt{x = 200}}}}$

Thus,

• $\textsf{Total 200 students appeared in the examination.}$