In a pure silicon (11
; = 10^16) crystal at 300 K, 1021 atoms of phosphorus are added per cubic meter. The new hole concentration will be :-
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2
Answer ⤵️
Given:-
Temperature = 300K
n
i
=10
16
/m
3
Atoms of phosphorous = 10
21
atoms
By using mass action law n
i
2
=n
e
n
h
⇒n
h
=
n
e
n
i
2
=
10
11
(10
16
)
2
=10
11
perm
3
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