In a quadratic equation mx2
+ 3x + 2 = 0 value of m for two
different values of x is 2 or −1
2
respectively
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for x =2
mx^2+3x+2=m(2)^2
+3(2)+2
4m+6+2
4m=8
m=8/4=2.
for x=-1
m(-1)^2+3(-1)+2
=m×1-3+2
=m-1
m=1.
hope it will help you.
mx^2+3x+2=m(2)^2
+3(2)+2
4m+6+2
4m=8
m=8/4=2.
for x=-1
m(-1)^2+3(-1)+2
=m×1-3+2
=m-1
m=1.
hope it will help you.
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