Math, asked by ayushlahiri8768, 11 hours ago

In a quadratic equation x² (m+2)x+6=0 roots a equal and opposite in sign then m is

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Answered by harshit5864
0

Answer:

In a quadratic equation x² (m+2)x+6=0 roots a equal and opposite in sign then m is

x2−bx=m+1m−1

(m+1)(x2)−(m+1)bx=(m−1)ax−c(m−1)

(m+1)x2−x[(m+1)b+(m−1)a]

(m+1)b+(m−1)a=0

mb+b+ma−a=0

m(a+b)=a−b

m=a+ba−b

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Answered by dishamalhan325
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Step-by-step explanation:

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