Question

In a quadratic polynomial whose one zero is7 and sum of zeroes-18,will be..

Answer 1

Since One zero=7

and Sum of zeroes= -18

Let other zero be x.

So 7+x= -18

x= -25

Other zero= -25

So required polynomial =

$= {x}^{2} - (soz)x + (poz) \\ = {x}^{2} - (7 + ( - 25))x + (7 \times ( - 25)) \\ = {x}^{2} - (7 - 25)x + (- 175) \\ = {x}^{2} + 18x - 175$

Hope it is helpful

Answer 2

Answer:

since one zero is 7

let another zero be x

Then, 7+x = -18

so, x= -25

Now, P(x) = x^2 - [7 + (-25)] x + 7× (-25)

= x^2 + 18 - 175

Step-by-step explanation:

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