in a quadrialteral ABCD & AB = BC= CA
CD = DA. If angle B 60° and angle c = 68°
Find angle B, angle C, angle D
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In a quadrilateral ABCD
given:-AB=BC=CA=CD=DA
TO find: angle B angle C angle D
in a quadrilateral ABCD the diagonal is bisect angle A and angle C
is the angle b is 60°and the angle c is68°
let's ABC is a triangle angle B is 60°and angle ACB is 68/2=34° .
so, 34+60-180=86°
angle CAB=86°
then 86 ×2=176°
68+60+172-360=60°
angle D=60°
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