Question

In a quadrilateral ABCD ∠ = (4)°, ∠ = 5(x+2)°, ∠ = (7 − 20)° ∠ = 6( + 3)°. Find each angle of the quadrilateral.​

Answer 1

Answer:

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Step-by-step explanation:

Angles of quadrilateral are,

(4x)°, 5(x + 2)°, (7x - 20)° and 6(x + 3)°.

4x + 5(x + 2) + (7x - 20) + 6(x + 3) = 360°

4x + 5x + 10 + 7x - 20 + 6x + 18 = 360° = 22x + 8 = 360°

22x = 360°- 8°

22x = 352°

x = 16°

Hence angles are,

(4x)° = (4 × 16)° = 64°,

5(x + 2)° = 5 (16 + 2)° = 90°,

(7x - 20)° = (7 × 16 - 20)° = 92°

6(x + 3)° = 6(16 + 3) = 114°