In a quadrilateral ABCD,A(2x+4)° and B=(2x-13)° and C=(3x+11)° and D=(4x-5)° find the measures of the angle
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Sum of all angles = 360°
(2x+4)° + (2x-13)° + (3x+11)° + (4x-5)° = 360°
=> 11x° - 3° = 360°
=> 11x° = 360° + 3°
=> 11x° = 363°
=> x = 33°
Hence, angle A = (66+4)° = 70°
Angle B = (66-13)° = 53°
Angle C = (99+11)° = 110°
Angle D = (264-5)° = 259°
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