Question

In a Quadrilateral ABCD, A +B = 150º and C=130º. Find D.​

Answer 1

Answer:

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\huge\tt{GIVEN:}

In a quadrilateral ABCD, D is equal to 150° and A= B = C

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\huge\tt{TO~FIND:}

A=B=C=X

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\huge\tt{SOLUTION:}

By angle sum property of quadrilateral we know,

➩ ∠A + ∠B + ∠C + ∠D = 360°

➩x + x +x+∠D = 360°

➩3x+∠D = 360°

➩3x = 360° – ∠D = 360° – 150°

➩3x = 210°

➩x = 70°

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Hence, ∠A = ∠B = ∠C = 70°

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Step-by-step explanation:

Answer 2

Answer:

Sum of angles in a quadrilateral is 360°

so A +B+C+D=360°

150°+130°+D=360°

280°+D=360°

D=360°-280°

D=80°

So answer is 80°