In a quadrilateral ABCD, (A + C) is 2 times (B + D). If A = 40', then B -
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∠A+∠C=2(∠B+∠D)
Also-
∠A+∠B+∠C+∠D=360
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∠A+∠C∠B+∠D=360
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2(∠B+∠D)+(∠B+∠D)=360
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⇒3(∠B+∠D)=360
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∠B+∠D=120
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∠B+40
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=120
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⇒∠B=80
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