In a quadrilateral ABCD, A + C is 2 times B + D, if A = 40° then C =
(A) 60° (B) 80° (C) 120° (D) None of these
Answers
Answered by
0
•A+C=2{B+D}[Given]
•A/2=B+D-C
•(40°)/2=B+D-C
•20°=B+D-C
•20°+C=B+D
•Therefore By Angle sum Property;
•A+20°+C+C=360°
•40°+20°+2C=360°
•60°+2C=360°
•2C=360°-60°
•C=300°/2
{C=150°}
!!Thank You!!
•A/2=B+D-C
•(40°)/2=B+D-C
•20°=B+D-C
•20°+C=B+D
•Therefore By Angle sum Property;
•A+20°+C+C=360°
•40°+20°+2C=360°
•60°+2C=360°
•2C=360°-60°
•C=300°/2
{C=150°}
!!Thank You!!
munnabhai33506p6pse0:
A+C=2(B+D)GIVEN
Not satisfied
As (A+C)/2=B+D is given so how can you place C in right hand side
Similar questions