In a quadrilateral ABCD, A + C is 2 times B + D, if A = 40° then C =
(A) 60° (B) 80° (C) 120° (D) None of these
Answers
Answered by
6
option b is correct...
80° is correct ans...
may help u...
and mark me brainliest.
80° is correct ans...
may help u...
and mark me brainliest.
christopherjenk:
no,it's b because it says twice the some.
hmm...right...
I think answer is-(d)
Is this correct
Can you please explain me
Is this correct
Yes
Yes
Thanx
Your welcome
Answered by
7
A+C=2(B+D)
NOW,
A+C+B+D=360. [ANGLES OF A QUADRILATERAL]
2(B+D)+B+D=360
2B+2D+B+D=360
3B+3D=360
3(B+D)=360
B+D=120
A+C=2(B+D)
A+C=2×120
A+C=240
40+C=240
C=200
HENCE OPTION (D)
NOW,
A+C+B+D=360. [ANGLES OF A QUADRILATERAL]
2(B+D)+B+D=360
2B+2D+B+D=360
3B+3D=360
3(B+D)=360
B+D=120
A+C=2(B+D)
A+C=2×120
A+C=240
40+C=240
C=200
HENCE OPTION (D)
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