in a quadrilateral ABCD a = x degree ,b= 60 +x degree , c = 60 degrees=130 degrees (find x)
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Answer:
A = x°
B = (60 + x)°
C = 60°
D = 130°
A + B + C + D = 360°
(Reason:- Angle sum property of a quadrilateral : angles of a quadrilateral add upto 360°)
x° + 60 + x° + 60° + 130° = 360°
2x° + 250° = 360°
2x° = (360 - 250)°
2x° = 110°
x° = 110°
2
x° = 55°
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