Question

In a quadrilateral ABCD, AB = 5 cm, BC= 37 cm,
CD = 35 cm, BD = 12 cm, and AD = 13 cm. Find
its are
solve it.​

Answer 1

Answer:

By applying heron's formula in triangle ABC having the sides 7 cm,6 cm and 9 cm, we have

s=

2

7+6+9

=11 cm

Area of triangle =

s(s−a)(s−b)(s−c)

=

11(11−7)(11−6)(11−9)

=

440

cm

2

Now, in triangle ADC having sides 15 cm,12 cm and 9 cm, we have

s=

2

15+12+9

=18 cm

=

18(18−15)(18−12)(18−9)

=54 cm

2

There, the area of quadrilateral ABCD=(

440

+54) cm

2