Math, asked by prantikchaudhary, 5 months ago

in a quadrilateral abcd ab||cd a:d=2:3 b:c=7:8 find measure of each angle

Answers

Answered by prince5132
8

GIVEN :-

  • In a quadrilateral abcd , ab || cd.
  • a:d = 2:3 , b:c = 7:8.

TO FIND :-

  • The measure of each angle of the quadrilateral.

SOLUTION :-

Let the ratio constant be "x".

  • ∠a = 2x.
  • ∠b = 3x.
  • ∠c = 7x.
  • ∠d = 8x.

Now, As we know that the sum of all the angle of a quadrilateral is 360°.

➳ ∠a + ∠b + ∠c + ∠d = 360°

➳ 2x + 3x + 7x + 8x = 360°

➳ 20x = 360°

➳ x = 360°/20

x = 18°.

Now , from the given value of x we will find the measure of each angle of the quadrilateral.

  • ∠a = 2x = 36°.
  • ∠b = 3x = 54°.
  • ∠c = 7x = 126°.
  • ∠d = 8x = 144°.

Hence the angles of quadrilateral are 36° , 54° , 126° , 144°.

Answered by Anonymous
7

\huge\mathfrak\pink{Question}

In a quadrilateral abcd, abcd, a:d=2:3 and b:c=7:8. Find measure of each angle.

\huge\mathfrak\pink{Given}

  • abcd is a quadrilateral.

  • abcd

  • a:d=2:3

  • b:c=7:8

\huge\mathfrak\pink{To\:find}

The measure of ∠a, ∠b, ∠c and ∠d.

\huge\mathfrak\pink{Solution}

Let the measure of ∠a, ∠b, ∠c and ∠d are 2x°, 7x°, 8x° and 3x° respectively.

We know that:

{\red{The\:sum\:of\:all\:angles\:of\:a\:quadrilateral}}\\{\red{is\:360°.}}

∠a+∠b+∠c+∠d=360

2x+7x+8x+3x=360

20x=360

x=(\frac{360}{20})

x=18

\huge\mathfrak\pink{Hence}

Since x=18,

  • ∠a=2x°=(2\times{18})°=36°

  • ∠b=7x°=(7\times{18})°=126°

  • ∠c=8x°=(8\times{18})°=144°

  • ∠d=3x°=(3\times{18})°=54°

\huge\mathfrak\pink{Therefore}

The measure of the angles are 36°, 126°, 144° and 54° respectively.

\huge\mathfrak\pink{Verification}

∠a+∠b+∠c+∠d=360

36+126+144+54=360

360=360

So, L.H.S= R.H.S.

Hence, verified.

\huge\mathfrak{\pink{Done࿐}}\\{\huge\mathfrak\blue{Hope\:this\:helps\:you.}}\\{\huge\mathfrak\orange{Have\:a\:nice\:day.}}

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