in a quadrilateral ABCD, AB = CD, AND angle ABC = angel BCD. prove that AD and BC are parallel
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First we will draw a diagonal between angle B and angle D
In triangle BDC and triangle ABD
AB = CD
BD = BD (COMMON)
BDC = ABD
TRIANGLE BDC IS CONGRUENT TO TRIANGLE ABD
So by CPCT,
BD = AB
Hence, BD II AB.
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