In a quadrilateral ABCD. AB || CD ZA ZD = 4.5 and B2C = 2:3. Find
the measure of each angle of the quadrilateral
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Answer:
∠A:∠D=2:3
Let ∠A and ∠D be 2x and 3x.
⇒ ∠B:∠C=7:8
Let ∠A and ∠D be 7y and 8y.
Since, AB∥CD and AD is a transversal.
∴ ∠A+∠D=180
. [ Interior angles on same side of transversal ]
⇒ 2x+3x=180
.
⇒ 5x=180
o
⇒ x=36
⇒ ∠A=2×36
=72
⇒ ∠D=3×36
=108
.
Since, AB∥CD and BC is a transversal.
∴ ∠B+∠C=180 [ Interior angles on same side of transversal ]
⇒ 7y+8y=180
⇒ 15y=180
∴ y=12
⇒ ∠B=7×12
=84
⇒ ∠C=8×12
=96
Step-by-step explanation:
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