In a quadrilateral ABCD, AB || CD, ZA: ZD = 4:5 and ZB: ZC = 2:3. Find
the measure of each angle of the quadrilateral,
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Answer:
first of all thanks for asking this question!! and here is your answer mate ♥️
Step-by-step explanation:
∵ ∠A : ∠D = 1 : 2
Let ∠A = x and ∠B = 2x
∵ ∠C : ∠B = 4 : 5
Let ∠C = 4y and ∠B = 5y
∵ AB ∥ DC
∴ ∠A + ∠D = 180°
x + 2x = 180°
3x = 180°
x = 60°
∴ A = 60°
∠D = 2x = 2 × 60 = 120°
Again ∠B + ∠C = 180°
5y + 4y = 180°
9y = 180°
y = 20°
∴ ∠B = 5y = 5 × 20 = 100°
∠C = 4Y = 4 × 20 = 80°
Hence ∠A = 60°; ∠B = 100° ; ∠C = 80°
and ∠D = 120°
(ii) Quadrilateral ABCD is a trapezium because one pair of opposite side is parallel.
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