Question

In a quadrilateral ABCD, AB II DC,if x=(4/3)y and y=(3/8)z.Find angle BCD,ABC,BAD​

Answer 1

Answer

In the figure AB||CD, If x=4/3y and y=3/8z find angle BCD, angle ABC and angle

∠BCD = 96° , ∠ABC = 84° , ∠BAD = 60°

Explanation

AB||CD

=> x + y + z = 180

=> 4y/3 + y + 8y/3 = 180

=> 4y + 3y + 8y = 540

=> 15y = 540

=> y = 36

x = 4y/3 = 4 * 36/3 = 48

x = 48

z = 8y/3 = 8 * 36/3 = 96

z = 96

∠BCD = z = 96°

∠ABC = x + y = 48 + 36 = 84°

∠BAD = 180 - x - 72

= 180 - 48 - 72

= 60°