Question

In a quadrilateral ABCD, AB II DC,if x=(4/3)y and y=(3/8)z.Find angle BCD,ABC,BAD

Answer 1

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▪️AB||CD

▪️=> x + y + z = 180

▪️=> 4y/3 + y + 8y/3 = 180

▪️=> 4y + 3y + 8y = 540

▪️=> 15y = 540

▪️=> y = 36

▪️x = 4y/3 = 4 * 36/3 = 48

▪️x = 48

▪️z = 8y/3 = 8 * 36/3 = 96

▪️z = 96

▪️∠BCD = z = 96°

▪️∠ABC = x + y = 48 + 36 = 84°

▪️∠BAD  = 180 - x - 72

▪️= 180  - 48 - 72

▪️= 60°

Hopes it help you✌️✌️