Math, asked by knightg442, 3 months ago


In a quadrilateral ABCD, AC = 15 cm. The perpendicular drawn from B and D respectively to. AC measure 8 cm and 9 cm. Find the area of the quadrilateral.


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Answers

Answered by xicacim193
2

Answer:

127.5 cm^2

Step-by-step explanation:

Please look at image and see diagram then look at solution:

AC = 15 cm   (given)

BF = 8 cm (given)

DE = 9 cm (given)

Area of quadrilateral = Area of ABC + Area of ADC

Area of triangle ABC = b*h/2 = AC * BF / 2 = 15 * 8 / 2 = 60 cm^2

Area of triangle ADC = AC * DE / 2 = 15 * 9 / 2 = 67.5 cm^2

Area of quadrilateral = 60 + 67.5 = 127.5 cm^2

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