In a quadrilateral ABCD, AC = 15 cm. The perpendicular drawn from B and D respectively to. AC measure 8 cm and 9 cm. Find the area of the quadrilateral.
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Answer:
127.5 cm^2
Step-by-step explanation:
Please look at image and see diagram then look at solution:
AC = 15 cm (given)
BF = 8 cm (given)
DE = 9 cm (given)
Area of quadrilateral = Area of ABC + Area of ADC
Area of triangle ABC = b*h/2 = AC * BF / 2 = 15 * 8 / 2 = 60 cm^2
Area of triangle ADC = AC * DE / 2 = 15 * 9 / 2 = 67.5 cm^2
Area of quadrilateral = 60 + 67.5 = 127.5 cm^2
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