Question

In a quadrilateral ABCD, AC = 15 cm. The perpendiculars drawn from B and D respectively to AC measure 8.2 cm and 9.1 cm. Find the area of the quadrilateral​

Answer 1

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$\sf{ar(ABCD) = \frac{1}{2} \times (sum \: of \: \: perp.) \times base} \\ \\ \sf{ = \frac{1}{2} \times (8.2 + 9.1) \times 15} \\ \\ \sf{ = \frac{1}{2} \times (17.3) \times 15} \\ \\ \sf{ = 17.3 \times 7.5} \\ \\ = \sf \underline{ 129.75 {cm}^{2} }$

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