Question

In a quadrilateral ABCD,AD=CD and angle A=90°,angle C=90°.prove that AB=BC​

Answer 1

Answer:

Below

Step-by-step explanation:

→ In △ABD & △BCD

AD=CD (Given) (Height)

BC=BC (Common) (Hypotenuse)

∠BAD=∠BCD (right angles)

∴△BAD≅△BCD (By RHS congruency Rule)

∴AB=BC ( By CPCT)

Answer 2

ANSWER :

In ∆s ABD and CBD,

angl A = angl C = 90°

BD = BD

AD = CD

So, by RHS rule,

∆ABD ≅ ∆CBD

Therefore, AB = BC