in a quadrilateral ABCD and Angle A equal to 50 degree and Angle B equals to angle C equals to angle D find Angle B and angle C and angle d
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Answered by
5
sum of quadrilateral
angle
A+B+C+D = 360
50 +3B = 360 ( b= c=d)
3B = 310
B = 130.3
so, b = c = d = 130.3°
Answered by
2
Answer:
given that,
A=50°
B=C=D
A+B+C+D=360°
50°+3(B)=360°
3B=360°-50°
3B=310°
B=310÷3
B=103.3°
B=C=D=103.3°
I hope it is helpful........................
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