In a quadrilateral ABCD angeA + angleB =90 degree. then prove that AC²+ BD²=AD²+BC²
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Step-by-step explanation:
AS shown in the attached diagram, ABCD is a quadrilateral, with ∠A + ∠D = 90°. We are to prove that AC² + BD² = AD² + BC². The sides AB and DC are produced to meet at "P".
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