Math, asked by shubham5536, 2 months ago

In a quadrilateral ABCD angeA + angleB =90 degree. then prove that AC²+ BD²=AD²+BC²

Answers

Answered by naveenjoshi01974

this is picture of the answer click and get answer

Step-by-step explanation:

AS shown in the attached diagram, ABCD is a quadrilateral, with ∠A + ∠D = 90°. We are to prove that AC² + BD² = AD² + BC². The sides AB and DC are produced to meet at "P".

I hope it's help you please like and mark me on brainliester✌✌✌

by divya ❣️❣️❣️❣️

Attachments:

Previous Question

Next Question

Similar questions

Physics, 1 month ago

what is the principal of displacement of water method(please answer in English)...

Math, 1 month ago

There are 102 teachers in a school of 3300 students Find the ratio of the number of teachers to the number of students ...

Math, 1 month ago

1 point X Х is equal to a(u,v) a(x,y) a(x,y) a(u,v) (a) -1 (b) 1 (c)0 (d) None...

Math, 2 months ago

solve 5(x+2)-2(3-4x)=3(x+5)-4(4-x)...

Biology, 2 months ago

explain why mammals excrete urea and not ammonia...

Math, 8 months ago

class9 find the value (8/3)℅...

English, 8 months ago

Prevention is_____ then care...

Math, 8 months ago

find value of X and y in 4x-7y =28 and 6x +5y =14...

In a quadrilateral ABCD angeA + angleB =90 degree. then prove that AC²+ BD²=AD²+BC²​

Answers

I hope it's help you please like and mark me on brainliester✌✌✌

by divya ❣️❣️❣️❣️

In a quadrilateral ABCD angeA + angleB =90 degree. then prove that AC²+ BD²=AD²+BC²