Math, asked by shubham5536, 11 days ago

In a quadrilateral ABCD angeA + angleB =90 degree. then prove that AC²+ BD²=AD²+BC²

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Answered by naveenjoshi01974

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Step-by-step explanation:

AS shown in the attached diagram, ABCD is a quadrilateral, with ∠A + ∠D = 90°. We are to prove that AC² + BD² = AD² + BC². The sides AB and DC are produced to meet at "P".

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by divya ❣️❣️❣️❣️

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In a quadrilateral ABCD angeA + angleB =90 degree. then prove that AC²+ BD²=AD²+BC²​

Answers

I hope it's help you please like and mark me on brainliester✌✌✌

by divya ❣️❣️❣️❣️

In a quadrilateral ABCD angeA + angleB =90 degree. then prove that AC²+ BD²=AD²+BC²