Question

In a quadrilateral ABCD, angle A=66°, angle B=(angle C+16)°; 2C = 6(x+4) and angle D (angle A-16). Calculate angle B and D.​

Answer 1

Answer:

angle= 66+3(x+4)+16+3(x+4)+50

360= 66+3x+12+16+3x+12+50

360=140+6x

360-156=6x

204=6x

204/6=x

34=x

angle B = 130

angle D= 50